lua_library()
This is liable to change in the future.
Alua_library() rule is used to group together Lua sources to be packaged into a top-level lua_binary rule.Arguments
name(required) #The short name for this build target.
srcs(defaults to[]) #The set of
.luafiles included in this library.base_module(defaults toNone) #The package for which the given specified sources and resources should reside in their final location in the top-level binary. If unset, the project relative directory that houses the BUCK file is used.
deps(defaults to[]) #Other
lua_library()rules which listsrcsfrom which this rule imports modules.visibility(defaults to[]) #List of build target patterns that identify the build rules that can include this rule as a dependency, for example, by listing it in their
depsorexported_depsattributes. For more information, see visibility.licenses(defaults to[]) #Set of license files for this library. To get the list of license files for a given build rule and all of its dependencies, you can use
buck query.labels(defaults to[]) #Set of arbitrary strings which allow you to annotate a build rule with tags that can be searched for over an entire dependency tree using
buck query attrfilter().
Examples
# A rule that includes a single .py file. lua_library( name = 'fileutil', srcs = ['fileutil.lua'], ) # A rule that uses glob() to include all sources in the directory which the # rule is defined. It also lists a resource file that gets packaged with # the sources in this rule. lua_library( name = 'testutil', srcs = glob(['testutil/**/*.lua'], )